b^2-4/3b+6

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Solution for b^2-4/3b+6 equation: 


b in (-oo:+oo)

b^2-((4/3)*b)+6 = 0

b^2+(-4/3)*b+6 = 0

b^2-4/3*b+6 = 0

DELTA = (-4/3)^2-(1*4*6)

DELTA = -200/9

DELTA < 0

b belongs to the empty set

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